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1) A quantity of gas at a temperature of 18oC has a volume of
124.5 cm3 at a pressure of
97.8 KPa. How many moles of gas are
there? PV=nRT
n=
[ mol K
][97.8 KPa ][0.1245dm3]
= 0.005 mol gas
[8.31 dm3
KPA][18oC + 273=K]
2) At a pressure of 105.2 KPa, 1.42 moles of a gas occupy 1.74 dm3.
What is the
temperature in Kelvin? PV=nRT
T = [
mol K ][105.2 KPa][1.74dm3] =
15.51K
[8.31 dm3
KPA ][1.42 mol ]
3) Hydrogen sulfide occupies 278.2 cm3 at 26oC and
standard pressure. What is the mass
of the hydrogen sulfide? PV=nRT
mass= [8.31 dm3
KPA][ 33.0g H2S][26oC +
273=K
] = 2.9Kg
[
mol K ][1 mole H2S ][101.3 KPa
][0.2782dm3]
4) Three and twenty-seven hundredths moles of carbon dioxide are in a vessel
of
undetermined size at 106.3 KPa and 21.8oC.
What is the volume of the vessel?
PV=nRT
V= [3.27 mol][8.31 dm3
KPA][21.8oC + 273=K] = 75.4 dm3
[
mol K ][106.3 KPa ]
5) A gas at 1.24oC occupies a 3.51 dm3 container.
If there are 3.34 moles of the gas,
at what pressure is the gas? PV=nRT
P= [3.34 mol][8.31 dm3
KPA][1.24oC + 273=K] = 2170 KPa
[
mol K ][3.51 dm3]
6) If 1.39 g of carbon monoxide is reacted with oxygen, what volume of carbon
dioxide
is produced at 12.3oC at 107.4KPa?
2CO + O2 --> 2CO2
mol CO2 = [1.39g
CO][1mol CO][2 mol CO2 ] = 0.05 mol CO2
[28 g CO ][2 mol CO ]
V= [0.05 mol][8.31 dm3
KPA][12.3oC + 273=K] = 1.09 dm3
[
mol K ][107.4 KPa ]
7) If 14.4 dm3 of ethane is combusted at 102.7oC and
99.3KPa, how many grams of
water will be produced?
2C2H6 + 7O2
--> 4CO2 + 6H2O
n=
[ mol K
][99.3 KPa
][14.4 dm3] = 0.46 mol C2H6
[8.31
dm3 KPa ][102.7oC +
273=K]
mass H2O
= [0.46 mol C2H6][6 mol H2O ][18
g H2O] = 24.8 g H2O
[2 mol C2H6][1 mol H2O]
8) What volume of C8H18 is required to fill a 1.4 dm3
airbag with CO2 if the wrecker truck
burns octane at STP? (Exhaust fumes are used to fill
airbags to upright flipped tractor
trailers.)
2C8H18 + 25O2
--> 16CO2 + 18H2O
n=
[ mol K
][101.3 KPa
][1.4 dm3] = 0.63 mol CO2
[8.31
dm3 KPa ][273K]
v C8H18
= [0.63 mol CO2][ 2 mol C8H18 ][22.4 dm3
C8H18] = 1.76 dm3 C8H18
[16 mol CO2 ][1
mol C8H18]
9) A scuba diver dives with a tank containing 5L of air. Twenty-two
percent of the air
is oxygen. If the diver produces 1.62 mol carbon
dioxide for every 2.05 mol of oxygen
he/she inhales, what is the volume (at STP) of carbon
dioxide produced if 4.2 L of air
are consumed at 202.6 KPa and 14.7oC?
air w 2.05 mol O2
--consumed yields-->1.62 mol CO2
4.2 L air = 4.2 dm3
air 4.2 dm3 air x 0.22 = 0.924 dm3 O2
n=
[ mol K
][202.6 KPa ][0.924 dm3]
= 0.078 mol O2
[8.31
dm3 KPa ][14.7oC +
273=K]
v CO2 = [0.078
mol O2][1.62 mol CO2][22.4 dm3 CO2]
= 1.38 dm3 CO2
[2.05 mol O2 ][1 mol CO2
]
10) If 34.6g of Zn are reacted with an excess of hydrochloric acid at
standard pressure,
what is the temperature of the hydrogen gas
produced if it occupies a 2.00 dm3
container?
2Zn + 2HCl --> ZnCl2
+ H2
n H2
= [34.6 Zn][1 mol Zn ][1 mol H2] = 0.265 mol
H2
[65.4 g Zn][2 mol Zn ]
T = [101.3
KPa ][2.00dm3 ][mol
K ]
= 92 K
[0.265 mol H2]
[8.31 KPa dm3]
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