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1a) How many moles of chlorine gas (Cl2) would react with 5 moles of sodium (Na)
according to the following chemical equation? (Balance equation.)
2Na + Cl2 -->
2NaCl
[5 mol Na][1 mol Cl2]
= 2.5 mol Cl2
[2 mol Na]
1b) Using the equation (after it is balanced) above, determine the amount of
product that
can be produced from 24.7 g Na.
[24.7g
Na][1 mol Na][2 mol NaCl][58g NaCl ] = 62 g NaCl
[23 g Na ][2 mol Na ][1 mol NaCl]
1c) How many molecules of product would be produced from 24.7g Na?
[24.7g Na][1
mol Na][2 mol NaCl][6.023 E23 molecules NaCl ] = 6.5
E23 NaCl
[23 g Na ][2 mol Na ][1 mol NaCl
] molecules
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2a) In the reaction 2C8H18 + 25O2 --> 16CO2
+ 18 H2O, the ratio of volumes of O2 to
CO2 is
25:16
2b) If 27.3g of C8H18 are combusted, what mass of water
will be produced?
[27.3 g C8H18][1
mol C8H18 ][18 mol H2O][18g H2O
] = 37.8 g H2O
[114g C8H18 ][2 mol C8H18][1
mol H2O]
2c) How many molecules of CO2 will be produced?
[27.3 g C8H18][1 mol C8H18
][16mol CO2
][6.023 E23 molecules CO2
] = 1.15 E24
[114g C8H18 ][2 mol C8H18][1
mol CO2]
molecules CO2
2d) How many atoms of H are in 2 mol of C8H18?
[2 mol C8H18][6.023
E23 molecules C8H18][18 atoms
H ]
= 2.2 E25 atoms
[1 mol C8H18
][1 molecule C8H18
]
H
2e) What is the percentage, by mass, of the H in 2 mol of C8H18?
[2 mol C8H18][6.023 E23
molecules C8H18][114 amu C8H18
] = 1.37 E26 amu
[1 mol C8H18
][1 molecule C8H18 ]
C8H18
[2.2 E25 atoms H][1amu H ] = 2.2 E25 amu H
[1 atom H]
2.2 E25 amu H * 100
= 16% H
1.37 E26 amu C8H18
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